Question

when two ohm resistance is connected between terminals of a cell current flow is 2A and 5 ohm resistance is connected then current is 1A. find out EMF and internal resistance of the cell?
give me answer fast...​

Answer 1

Answer:

HEY MATE HERE YOUR ANSWER

MARK AS BRAINLIEST PLEASE

Explanation:

Answer 2

PART-I

• Current flowing( I ) = 2 A

• Resistance of the resistor connected ( R )= 2 Ω

⟹ E = I( R + r )

⟹ E = 2 ( 2 + r )   .... (1)

PART -II

• Current flowing (I)= 1 A

• Resistance of the resistor connected ( R)= 5 Ω

⟹ E = I( R + r )

⟹ E = 1 ( 5 + r )   ....(2)

Equating equation (1) and (2) we get ,

⟹ 2 ( 2 + r ) = 1 ( 5 + r )

⟹ 4 + 2r = 5 + r

⟹ 2r - r = 5 - 4

⟹ r = 1  Ω

∴The internal resistance  of the cell is 1 Ω

Substituting the value of r in ( 1 ) we get ,

⟹ E = 2 ( 2 + 1  )

⟹ E = 2 ( 3 )

⟹ E = 6 V

∴The EMF of the cell is 6 V