Question

When two parallel lines are cut by a transversal,
i) If the measures of a pair of co-interior angles are (2a)° and
(3a−10)°; find the value of 'a’.
ii) If the measures of a pair of corresponding angles are (2b+15) °
and (3b−7) ° ; find the value of ‘b


please answerr

Answer 1

ANSWER:

• GIVEN THE MEASURE OF 2 CO - INTERIOR ANGLES
• $\\ \\ ( {2a)}^{o} \: \: and \: \: \: {(3a - 10)}^{o}$

WE KNOW THAT,

the lines are parallel, the co-interior angles are supplementary.

(2a)° + (3a- 10)°=180°

5a = 190°

a = 38°

• GIVEN THE MEASURE OF 2 CORRESPONDING ANGLES

$\\ \\ \\ ( {2b + 15)}^{^{o} } \: \: \: and \: \: \: ( {3b + 7)}^{^{o} }$

We know that ,

if the lines are parallel, the corresponding angles are equal.

So ,

(2b+15)° = (3b-7)°

2b-3b = -7-15

- b= - 22

b = 22° ( Answer)

Answer 2

Answer:

The boiling point of a substance is the temperature at which the vapor pressure of a liquid equals the pressure surrounding the liquid and the liquid changes into a vapor.