Question

When two particles of mass m are dropped from height h and 2h find ratio to reach ground?

Answer 1

This is the answer to your question

Answer 2

Answer:

1/$\sqrt{2}$

Explanation:

Initially u =0 ,

Then we are assuming that

s =\frac{1}{2}  g t^2

s $\alpha$ t^2

Then

\frac{t1}{t2} = $\sqrt{}$\frac{s1}{s2}

where s1 = k

s2 = 2k

\frac{t1}{t2} = 1/$\sqrt{2}$

#SPJ3