When two-point charges are placed some distance apart in vacuum experience a force of 800 N, what will be the force between charges in a medium of dielectric constant 80?
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Answer:
F/4
F=
4πϵ
0
ϵ
r
2
Fd
2
q
1
q
2
Fα
ϵ
r
1
For vacuum ϵ
r
=1,
ϵ
r
of medium =4
∴ F for medium will be F/4.
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