Question

when two resistance 50/3Ω and unknown resisatance are connected in the left and right gaps of a meter bridge ,the balance length is 70cms .when resistance ""x""is connected in parallel to 50/3Ω the balance becomes 35cm .the value of "'x "' is
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Answer 1

Answer:

abcdefghijklmnopqrstuvwxyz (don't know) it is mind twisting question ..

Explanation:

Brainliest please

Answer 2

Answer:

The value of x is 5cm.

Explanation:

According to question :-

$\frac{50}{3}$/x = 70/100-70

$\frac{50}{3x}$ = $\frac{7}{3}$

x = $\frac{50}{7}$

now , x is connected in parallel with 50/3

R = $\frac{50}{3}$× x/ $\frac{50}{3}$ + x

R = 50x/ 50 +3x

again,

50x/50 +3x / $\frac{50}{7}$ = $\frac{35}{100 - 35}$

$\frac{7x}{50+ 3x}$ = $\frac{35}{65}$

13x = 50+3x

x = 5cm