When two resistance are connected in parallel the
equivalent resistance is 6/5ohm When one of the
resistance is removed then the effective resistance is
2 ohm The resistance of the wire removed will be
(a) 3 ohm
(b) 2 ohm
(c) 3/5ohm
(d) 6/5ohm
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4
Answer:
3 ohm.
Let the other resistance be K ohm.
If second resistance is removed, eff. resistance = 2 ohm.
2K / 2 + K = 6/5. K = 3 ohm.
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