Question

When two resistance wires are in the two gaps of a meter bridge, the balance point was found to be 1/3 cm from the zero end. When a 6 Ωresistor is connected in series with the smaller of the two resistances, the balance point shifted to 2/3 cm from the same end. Find the resistances of the two wires.

Answer 1

Answer:

6ohm, 1800ohm

Explanation:

P/Q=l1/l2

p is smaller resistance

P/Q=(1/3)/100

=1/300

When 6ohm connected series with p

Reff=P+6

P+6/Q=2/300

dividing both

p+6/p=2/1

p+6=2p

p=6ohm

q=1800ohm