when two resistor R1 and R2 connected in parallel the net resistance is 3 ohm
when connected is series it is 16 ohm find R1ANDR2
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Series: R1+R2=16 , R2=16-R1
Parallel: (R1*R2)/(R1+R2)=3
R1*R2/16= 3
R1*R2= 48
R1(16-R1)= 48
16R1-R1^2= 48
R1^2-16R1+48= 0
(R1-4)(R1-12)= 0
R1=4 ,R1=12
R1= 4[Ω] , R2= 12[Ω]
or
R1= 12[Ω] , R2= 4[Ω]
Parallel: (R1*R2)/(R1+R2)=3
R1*R2/16= 3
R1*R2= 48
R1(16-R1)= 48
16R1-R1^2= 48
R1^2-16R1+48= 0
(R1-4)(R1-12)= 0
R1=4 ,R1=12
R1= 4[Ω] , R2= 12[Ω]
or
R1= 12[Ω] , R2= 4[Ω]
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0
The value of R1 is 12 ohm and of R2 is 4 ohm
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