Question

When two resistors are connected in series their effective resistance is 80ohm when they are connected in parallel their effective resistance is 20 ohm what are the values of the two resistance
1

Answer 1

Answer:

Yes definitely both resistance must be same 40 ohm's.

Yes definitely both resistance must be same 40 ohm's.In series equivalent resistance is R1+R2=80 ohm's.

Yes definitely both resistance must be same 40 ohm's.In series equivalent resistance is R1+R2=80 ohm's.In parallel equivalent resistance is

Yes definitely both resistance must be same 40 ohm's.In series equivalent resistance is R1+R2=80 ohm's.In parallel equivalent resistance is(R1.R2)/(R1+R2)=20 ohm's.

Yes definitely both resistance must be same 40 ohm's.In series equivalent resistance is R1+R2=80 ohm's.In parallel equivalent resistance is(R1.R2)/(R1+R2)=20 ohm's.So R1.R2=1600 ohm's.

Yes definitely both resistance must be same 40 ohm's.In series equivalent resistance is R1+R2=80 ohm's.In parallel equivalent resistance is(R1.R2)/(R1+R2)=20 ohm's.So R1.R2=1600 ohm's.By solving underlined eq by using formula of quarditic equation

Yes definitely both resistance must be same 40 ohm's.In series equivalent resistance is R1+R2=80 ohm's.In parallel equivalent resistance is(R1.R2)/(R1+R2)=20 ohm's.So R1.R2=1600 ohm's.By solving underlined eq by using formula of quarditic equation(R1+R2)^2-(R1-R2)^2=4R1.R2

Yes definitely both resistance must be same 40 ohm's.In series equivalent resistance is R1+R2=80 ohm's.In parallel equivalent resistance is(R1.R2)/(R1+R2)=20 ohm's.So R1.R2=1600 ohm's.By solving underlined eq by using formula of quarditic equation(R1+R2)^2-(R1-R2)^2=4R1.R2So we get finally R1=R2=40 ohm's.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

40

step by step explaination

when connected in series 40+40 =80

when connected parellel 40/2=20

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