when two resistors are connected in series,their effective resistance is 80ohm.when they are connected in parallel, their effective resistance is 20ohm.What are the values of the two resistors
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2
Answer:
Let the two resistances be R
1
and R
2
.
Series connection R
s
=R
1
+R
2
Or 80=R
1
+R
2
⟹ R
1
=80−R
2
Parallel connection :
R
p
=
R
1
+R
2
R
1
R
2
Or 20=
80
R
1
(80−R
1
)
Or R
1
2
+80R
1
−1600=0
⟹ R
1
=40Ω
So, R
2
=80−40=40 Ω
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Answer:
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