Question

when two resistors are joined in series the equivalent resistance is 90 ohm when the same resistors are joined in parallel then the equivalent resistance is 20 ohm calculate the resistance of two resistance​

Answer 1

Answer:

Let two resistances be p,q

Given

p+q=90

(pq)/(p+q)=20

pq=1800

p=1800/q

1800+q^2=90q

q^2-90q+1800=0

q^2-60q-30q+1800=0

q= 60, 30

p=30,60

The two resistances are 30 ohm,60 ohm