Question

When two resistors of (600+3)ohm and
(3006) ohm are connected in parallel, value
of the equivalent resistance is
1) 200 ohm + 1.5% 2) 200 ohm + 3.5%
3) 200ohm + 9% 4) 200ohm​

Answer 1

Answer:

3) 200ohm +9% is the correct answer..

Explanation:

Whenever two resistors are connected in parallel,

We use R1×R2/R1+R2

So 600×300/300+600 =200 ohm

The errors always get added up....

3+6=9%

Answer 2

Given,

Two resistances that are to be connected in parallel = (600 + 3)ohm and (300 + 6) ohm.

To find,

The equivalent resistance

Solution,

The equivalent resistance is (200+9) ohm. (Option 3)

We can simply solve the numerical problem by the following procedure.

We know that,

When two resistance are connected in parallel, the resistance value decreases, and the current value increases.

Also,

∴ $\frac{1}{Req} = \frac{1}{R1} + \frac{1}{R2}$

⇒ $\frac{1}{Req}= \frac{1}{600}+\frac{1}{300}$

⇒ $\frac{1}{Req} = \frac{1}{100} (\frac{1}{3} + \frac{1}{6} )$

⇒ $\frac{1}{Req}= \frac{1}{100}(\frac{9}{18} )$

⇒ Req = 200 ohm

Thus, the value of the equivalent resistance is 200 ohm.

Now,

Noting that there was an error in the value of the two resistance given. The error in the equivalent resistance will be the sum of the errors of the two resistances.

Thus,

The error in the equivalent resistance is 9.

As a result, the equivalent resistance is (200+9) ohm. (Option 3)