When two resistors of resistance R1 and R2 they are connected in parallel the net resistance is 3 ohm when they are connected in series the value 16 ohm calculate R1 and R2
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7
Answer:
Explanation:
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When they are connected in parallel
1/Req=1/R1+1/R2
So by taking the LCM of R1 and R2 we get it it's value is got by cross multiplicating
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I have a doubt how R1R2
Answered by
0
Answer: here's the answer
Explanation:
R1 and R2 are in parallel combination.
R
1
p R R
1 1
1 2
= +
R R
R R
1 2
1 2 #
+ = 3 ...(1)
When R1 and R2 are in series combination.
Rs = R R 1 2 + = 16 Ω
R R 1 2 + = 16 ...(2)
After solving equation (1) and equation (2),We get
R R 1 16 48 2 − +1 = 0
^ ^ R R 1 1 − − 4 12 h h = 0
R1 = 4 12 Ω Ω ,
R2 = 12 4 Ω Ω
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