Question

When two resistors of resistance R1 and R2 they are connected in parallel the net resistance is 3 ohm when they are connected in series the value 16 ohm calculate R1 and R2

Answer 1

Answer:

Explanation:

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When they are connected in parallel

1/Req=1/R1+1/R2

So by taking the LCM of R1 and R2 we get it it's value is got by cross multiplicating

Answer 2

Answer: here's the answer

Explanation:

R1 and R2 are in parallel combination.

R

1

p R R

1 1

1 2

= +

R R

R R

1 2

1 2 #

+ = 3 ...(1)

When R1 and R2 are in series combination.

Rs = R R 1 2 + = 16 Ω

R R 1 2 + = 16 ...(2)

After solving equation (1) and equation (2),We get

R R 1 16 48 2 − +1 = 0

^ ^ R R 1 1 − − 4 12 h h = 0

R1 = 4 12 Ω Ω ,

R2 = 12 4 Ω Ω

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