When two resistors of resistances R, and R, are connected in parallel,the net
resistance is 3 Ohm. When connected in series, its value is 16 Ohm. Calculate the values of R1 and R2.....?¿?¿
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5
Answer:
R + r = 16
R × r / R + r = 3..............~
Given R + r= 16..
R × r / 16 = 3
R × r = 48
R = 16 - r
16r - r^2 = 48
qyadratic equation banegi....
r^2 - 16r + 48 = 0
two root aayegi...
ek 12 aaor ek 4....
bas ban gya .....
Answered by
1
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