Question

when two right angled vector of magnitude 8 units and 26unitswhat is the magnitude of resultant vector​

Answer 1

Answer:

Explanation:

Given :

• Two right angled vector of magnitude 8 units and 26 units.

To Find :

• The magnitude of resultant vector.

Solution :

Let, resultant vector be "R".

The resultant vector forms the hypotenuse while the constituent vectors form the other two sides.

Hence, Apply pythagoras theorem,

$\longrightarrow \sf \: R = \sqrt{(8 {}^{2} + 26) {}^{2} } \\ \\ \longrightarrow \sf \: R = \sqrt{(64 + 676)} \\ \\ \longrightarrow \sf \: R = \sqrt{(740)} \\ \\ \longrightarrow \sf \red{R =27.2 \: units }$

Hence :

The magnitude of resultant vector is 27.2 units.

Answer 2

$\Large \mathfrak{ \blue{Given : }}$

• Two right angled vector of magnitude 8 units and 26 units.

$\Large \mathfrak{ \color{green}{To Find : }}$

•  The magnitude of resultant vector.

$\Large \mathfrak{ \orange{Solution :}}$

• Let, resultant vector be "R".

• The resultant vector forms the hypotenuse while the constituent vectors form the other two sides.

Applying Pythagoras Theorem,

$\begin{gathered} { \purple{\implies \sf \: R = \sqrt{(8 {}^{2} + 26) {}^{2} }}} \\ \\ { \purple{\implies \sf \: R = \sqrt{(64 + 676)}}} \\ \\ { \purple{\implies\sf \: R = \sqrt{(740)}}} \\ \\{ \boxed{ { \red{\implies \sf {R =27.2 \: units }}}}}\end{gathered}$

Hence, The magnitude of resultant vector is 27.2 units.