Question

When two right angled vectors of magnitude 7 units and 24 units combine, what is
the magnitude of their resultant?​

Answer 1

One vector = 7units

Second vector = 24units

∅(angle between them) = 90°

Resultant vector =

$\sqrt{7 {}^{2} + 24 {}^{2} + 2 \times 7 \times 24 \times cos90}$

$\sqrt{49 + 576 + 336cos90}$

Since , cos90° = 0

$\sqrt{49 +576 }$

$\sqrt{625}$

$25$

Therefore Resultant vector is 25units

Cheers!

Answer 2

Apply the triangle law.....you will get a right angled triangle awith 2 sides of given vectors' magnitude and hypotenuse as resultant .

Apply pythagoras or use

R(mod)=sqrt.(A(mod)^2+B(mod)^2+2mod(A)mod(B) ×cosine of angle)

In either case the resultant will be 25 units.

Early answer credits......#upar dekho lol