when two simple pendulums of two diffrent length if one is short and one is longer set into vibration with same phase again they are in same phase the shorter pendulum completed (N) oscillation to find the value of (N)?
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Explanation:
If T1 be the time period of pendulum 1(l=1.21) and T2 that of the 2nd(l=1m) one,
We can say T1T2 = √(L1L2) or T1T2 = 1.1=1110
I.e 10T1=11T2
That means 10 oscillations of T1 is completed in the same time in which 11 oscillation of T2 is completed . Hence after that time thay will again be in the same phase, i.e swinging together.
If T1 be the time period of pendulum 1(l=1.21) and T2 that of the 2nd(l=1m) one,
We can say T1T2 = √(L1L2) or T1T2 = 1.1=1110
I.e 10T1=11T2
That means 10 oscillations of T1 is completed in the same time in which 11 oscillation of T2 is completed . Hence after that time thay will again be in the same phase, i.e swinging together.
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