When two sounds differ by 30 db the louder one is more intense than the other by?
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The louder one is 1000 times more intense than the other one.
Explanation :
We know that decibel is measured in the logarithmic scale and is given by the relation,
dB = 10 log(I₂/I)
Since the difference between both the sound is 30 dB
Hence,
30 = 10 log(I₂/I)
=> log(I₂/I) = 3
=>(I₂/I) = 10³
=> (I₂/I)= 1000
Hence the louder one is 1000 times more intense than the other one.
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