when two times a number is added to its square we get 8 find the number by making the equation properly
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Answer:
I think your question is :
when 2times a number is added to it's square we get 8 . find the number by making the equation properly?
Answer:
According to the correction required number is 1.
Step-by-step explanation:
According to the question let the required number be a,
It is given in the question that when 7 times a number is added to it's square we get 8.
Now,
7 times of the number = 7a
Square on the number = a^2
Adding 8 times of the number to the square of the same number : 7a + a^2
According to the question, result is 8.
So,
= > 7a + a^2 = 8
= > a^2 + 7a = 8
= > a^2 + 7a - 8 = 0
= > a^2 - a + 8a - 8 = 0
= > a( a - 1 ) + 8( a - 1 ) = 0
= > ( a - 1 ) ( a + 8 ) = 0
= > a = 1 or - 8
Taking positive value.
Therefore, required number is 1.
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Step-by-step explanation: