When two tuning forks are struck simultaneously 4 beats per second now some wax is attached on the prong of the fork 2 when two tuning forks are sounded again 6 beats per second are heard if frequency of fork 1 is 200 htz then what was original frequency of fork 2?
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1 fork frequency is 200 difference of freq. 4 beat per sec means 200+4,200-4 ho sakti hai wax 2. fork par load kiya gya hai and wax loading se frequency decrease hoti hai but beat changed and now 6 beat per sec agar fork ke 200+4 = 204 hoti toh wax loading par beat kam hota kyunki difference kam hota but 196 hoga toh wax lagane par difference increase hoga means original freq. is 196hz
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