When two unbiased coins are tossed ,the probability of obtaining not more than 3 heads?
Answers
Given : two unbiased coins are tossed
To Find : probability of obtaining not more than 3 heads
Solution:
two unbiased coins are tossed
Each coin has two out comes Head & Tail
Two coins are Tossed
Hence total possible outcomes = 2 x 2 = 4
n(S) = 4
HH , HT , TH , TT
E = obtaining not more than 3 heads
= obtaining 3 or less than 3 Heads
= 0 Head + 1 Head + 2 Head + 3 Head
0 Head = 1 ( TT)
1 Head = 2 ( HT , TH)
2 Head = 1 ( HH)
3 Head = 0
=> n(E) = 1 + 2 + 1 + 0 = 4
Probability ( E) = n(E)/n(S)
= 4/4
= 1
probability of obtaining not more than 3 heads = 1
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