When two unbiased dice are rolled.What is the probability of getting sum of digits as 7 or 10? Select one: a. 3/36 b. 1/6 c. 1/4 d. 1/18
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1/4
total no. of outcomes =6*6= 36
no. of cases for 7= 6 ((1,6),(6,1),(2,5),(5,2),(3,4),(4,3))
no. of cases for 10 =3 (5,5),(6,4),(4,6)
no. of cases for 7 or 10 = 6+3=9
probability {9/36) =1/4
total no. of outcomes =6*6= 36
no. of cases for 7= 6 ((1,6),(6,1),(2,5),(5,2),(3,4),(4,3))
no. of cases for 10 =3 (5,5),(6,4),(4,6)
no. of cases for 7 or 10 = 6+3=9
probability {9/36) =1/4
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