Question

when v<v0 the frictional force will be up the slope and that a car can be parked only if tan theta≤ coefficient of static friction . why?​

Answer 1

Answer:

here your answer:

tan(${\theta}$) < ${\mu}$ is what?

》$\frac {sin(\theta)}{cos(\theta)}$ < ${\mu}$

• lets put mg on both sides...

mgsin(${\theta}$)< ${\mu}$mg${cos(\theta)}$

☆${\mu}$mg${cos(\theta)}$is nothing but limiting friction.

☆mgsin(${\theta}$) is the sliding force which is acting in along downside of the incline plane.

#and limiting friction which is acting upward the plane should be greater than the mgsin(${\theta}$) to avoid slipping of the vehicle in the plane.

and thats how the car will be parked otherwise it will flow down.

☆ and as its given the velocity is less than the safe speed so the friction is has to be applied in the up for balance the inward centripetal force by normal ,so that it does not slip inside.

see the attachment pls! you will understand better!

♧hope it helps!♧