when velocity becomes three times the original velocity what is the new kinetic energy
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Hey mate!
Initial K.E. = 1/2mv^2
Final K.E. = 1/2m(3v)^2
=>1/2m(27v^2)
=>13.5mv^2.
That's your answer!
Hope it helps :)
Please mark me the brainliest.
Initial K.E. = 1/2mv^2
Final K.E. = 1/2m(3v)^2
=>1/2m(27v^2)
=>13.5mv^2.
That's your answer!
Hope it helps :)
Please mark me the brainliest.
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