When volume of an ideal gas is increased two times and temperature is decreased half of its initial temperature then pressure becomes?
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Explanation:let the initial conditions be like pv=nrt so from here,p=(n/vrt)..
Case 2##vol=2v , t=t/2 ,so the equation becomes p=2n/2vrt=n/vrt...so from here you can say pressure remains same as initial...
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