Question

When volume of an ideal gas is increased two times and temperature is decreased half of its initial temperature then pressure becomes?

Answer 1

Answer:

Explanation:let the initial conditions be like pv=nrt so from here,p=(n/vrt)..

Case 2##vol=2v , t=t/2 ,so the equation becomes p=2n/2vrt=n/vrt...so from here you can say pressure remains same as initial...

Thanks hope it will help....