Question

when walking at 3/4 of normal speed, a person lays for 15 minutes, its normal time is how many minutes

Answer 1

Let s = his normal speed

t = his normal time

Then

D = (3/4)s * (t+16)

Since the distance is the same we can equate this to his regular day which is D = s*t

s*t = (3/4)s * (t+16)

t=48

Answer: B