Question

when we drop an iron ball in mercury it will a)immerse b)dissolve c)float d)none of these.​

Answer 1

Answer:

it will float

Explanation:

It is because the density of iron ball is lesser than the density of mercury so the upthrust force acting on the solid ball is greater than the weight of the solid ball which results to float the solid ball.

Answer 2

Answer:

The answer is (c) float.

Explanation:

This question requires understanding of density concept:

• Density of mercury $=13 g/cm^{3}$
• Density of iron $=7.9 g/cm^{3}$

• Density of any object is defined as mass per unit volume i.e. $Density= \frac{mass}{volume}$

• An object immerses only when the density of the object in question is more than the medium in which it is kept.
• Dissolution of any object in a medium happens when there is intermolecular reaction between them.
• Floating happens when the density of an object is less than the medium. Here, the density of iron is less than mercury.
• Higher density of mercury allows it to have enough buoyant force to hold the iron ball and balance its weight and that is the reason of it floating on the surface of mercury.