When we start to think about factoring x^2+6x+8, we think of two/2 numbers.
What are those two/2 numbers?....
Answers
Answer:
hello mate!
Step-by-step explanation:
I see, You are asking us, What are those 2 numbers which are used as The numbers to split up the middle term.
basically,
you can go with Identity 4,
x+a(x+b)=x²+x(a+b)+ab
so, The 2 number we choose, It need to be,
a+b= middle term
(a) × (b)= Last term.
so,
X²+6x+8.
factors of 8= 2×4, 1×8.
4 × 2 = 8.
4 + 2 = 6.
hence, it is 4 + 2 = 6.
so, substituting these values in the identity,
(X= X, A=4, B=2),
X²+ X(4+2) +.(4×2)= x+a(x+b)
x²+4x+2x+8.= x+4(x+2)
x(x+4)+2(x+4)
x+2(x+4).
, I have factorized it in both ways, Using Identities or regrouping Methodology.
to your question,
Those 2 required numbers are,
4 and 2.
thank you mate!
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Answer:
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