When white phosphorus reacts with costic soda then what happened next ?
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Gibb to get it done and done it before I go
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P4+3NaOH+3H2O+3H2O→PH3+3NaH2PO2,oxidation state of P in the LHS side=0
In right side
PH3
x+3(+1)=0
x=-3
NaH2PO2
1+2(1)+x+2(-2)=0
thus from 0 oxidation state there is both reduction in the oxidation no and increase in oxidation no occur.
The first reaction is reduction and the second reaction is oxidation.Such type of redox reaction from the same molecule.ie one undergoes oxidation & the other undergoes reduction is called disproportion reaction.
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P4+3NaOH+3H2O+3H2O→PH3+3NaH2PO2,oxidation state of P in the LHS side=0
In right side
PH3
x+3(+1)=0
x=-3
NaH2PO2
1+2(1)+x+2(-2)=0
thus from 0 oxidation state there is both reduction in the oxidation no and increase in oxidation no occur.
The first reaction is reduction and the second reaction is oxidation.Such type of redox reaction from the same molecule.ie one undergoes oxidation & the other undergoes reduction is called disproportion reaction.
Thank you
Mark me as Brainlist
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