when will the simaltanous equations a1x+b1y+c1=0
and a2x+b2y+c2=0 have infinite number of solution
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Answered by
0
Answer:
when (a1/a2)=(b1/b2)=(c1/c2)
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1
Answer:
This will happen when the two lines are coincident that is
(a1/a2) =(b1/b2)=(c1/c2)
Step-by-step explanation:
For eg 4x+3y+2z=0 and 8x+6y+4z=0 has similar solution but infinite as their graphs are coincidental. So the may not be having a particular solution also
(4/8)=(3/6)=(2/4)={1/2}
Therefore they are coincident and are having infinite solutions.
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