Math, asked by sumitraghosh779, 10 months ago

when will the simaltanous equations a1x+b1y+c1=0
and a2x+b2y+c2=0 have infinite number of solution ​

Answers

Answered by Sukin272
0

Answer:

when (a1/a2)=(b1/b2)=(c1/c2)

Answered by dharun1
1

Answer:

This will happen when the two lines are coincident that is

(a1/a2) =(b1/b2)=(c1/c2)

Step-by-step explanation:

For eg 4x+3y+2z=0 and 8x+6y+4z=0 has similar solution but infinite as their graphs are coincidental. So the may not be having a particular solution also

(4/8)=(3/6)=(2/4)={1/2}

Therefore they are coincident and are having infinite solutions.

Similar questions