When would the electric field at a point due to a uniformly charged glass bangle and a point charge of the same magnitude have the same value.l
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Answer:
Answer:
(i) At a point P outside the spherical shell :
Let
E
be the electric field at P. The electric field through an elemental surface d
s
is
dϕ=
E
.d
s
∴ Total electric flux through the gaussian surface is
ϕ=∮
S
Eds=E∮
S
ds=E×4πr
2
ϕ=
ϵ
0
q
E×4πr
2
=
ϵ
0
q
E=
4πϵ
0
1
.
r
2
q
(for r>R)
(ii) At a point P inside the spherical shell:
In this case charge enclosed =0
E×4πr
2
=0
E=0 (for r<R)
Explanation:
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