Question

when x=0 y=1 z=2 what is x2 y2 +z2 -2xyz

Answer 1

Answer:

Given x

2

+y

2

+z

2

−xy−yz−zx=0

2x

2

+2y

2

+2z

2

−2xy−2yz−2zx=0

(x

2

−2xy+y

2

)+(y

2

−2yz+z

2

)+(z

2

−2zx+x

2

)=0

⇒ (x+y)

2

+(y−z)

2

+(z−x)

2

=0

⇒ x=y=z=k

⇒

z

x+y

=

k

2k

=2

Step-by-step explanation:

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Answer 2

$\large\bf{\underline\orange{Answer \:↝}}$

If x = 0

y = 1

z = 2

Then, x² + y² + z² + 2xyz

(0)² + (1)² + (2)² - 2(0)(1)(2)

1 + 4 - 4

1