Question

When (x + 1) is divides ax^4 - 3x^3 + 8x^2 - 6x + 1, then the remainder will be
1) 2a +9
2) a + 18
3) 2a + 11
4) 2a +17​

Answer 1

Answer:

we divide f(x)=3x

3

+x

2

+2x+5 by g(x) we get q(x)=(3x−5) as quotient and r(x)=(9x+10) as remainder.

By using division algorithm,

f(x)=g(x)q(x)+r(x)

⟹3x

3

+x

2

+2x+5=g(x)(3x−5)+(9x+10)

⟹g(x)=

(3x−5)

3x

3

+x

2

+2x+5−9x−10

⟹g(x)=

(3x−5)

3x

3

+x

2

−7x−5

Hence, g(x)=x

2

+2x+1

Answer 2

Answer:

Step-by-step explanation

:First, we will equate x+1 with

 :x=-1

therefore by putting values we get : a-3+8+6+a=

2a+11