when x=(-1), y = 2 and z = 3, find the value of x^3 + y^3 + z^3- 3xyz
Answers
Answered by
1
Answer:
We have,
x=2,y=1,z=−3
Since,
x
3
+y
3
+z
3
−3xyz
On putting the values of x,y,z, we get
=2
3
+1
3
+(−3)
3
+3(2)(1)(−3)
∴x
3
+y
3
+z
3
−3xyz=0
Hence, this is the answer.
Answered by
0
Answer:
x^3+ y^3+ z^3-3xyz
=(-1)^3 + (2)^3 + (3)^3 -3×(-1)×(2)× (3)
= -1 + 8 +27 - (-9)
= 36+9
= 45
so answer is 45
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