when x=2 and y=(-3)
(x + y)³=x³+y³+3x²y + 3xy²
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Answer:
x=2 & y=(-3)
(x+y)³=x³+y³+3x²y+3xy²
then
(2+3)³= (2)³+(-3)³+3×(2)²×-3+3×2×(-3)²
= 8-27+ 3×4×-3+ 3×2×9
= 8-27 -36 + 54
= -1
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