Math, asked by s1854snigdha13041, 8 months ago

When x^3-2x^2 + ax - b is divided by x^2 - 2x - 3, the remainder is x-6. The values of
a and b are respectively
(a) - 2-6
(b) 2 and - 6 (c) - 2 and 6 (d) 2 and 6​

Answers

Answered by Raghavrocks17
0

Answer:

ans is b

Step-by-step explanation:

Answered by pragna845
0

Answer:

ANSWER

x

3

−2x

2

+ax−b is divided by x

2

−2x−3 and the remainder obtained is x−6.

Now, the first term in the quotient will be x since the coefficient of x

3

is 1.

So, x(x

2

−2x−3)=x

3

−2x

2

−3x, which when subtracted from the dividend gives (a+3)x−b

Since the degree of the above term is less than the divisor, it is the remainder and so we equate it to x−6

Hence, a+3=1 and b=6

⇒a=−2,b=6

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