Question

when x^3+bx^2+3x+4 is divided by x-2 remainder is 18, find b

Answer 1

Answer:

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Answer 2

Answer

x - 2 = 0

x = 0

p(x) = x^3 + bx^2 + 3x + 4

p(2) = (2^3) + b(2^2) + 3(2) + 4 = 18

=> 8 + 4b + 6 + 4 = 18

=> 4b = 0

=> b = 0