Math, asked by celineong1016, 4 hours ago

When x^4 -ax^3+bx^2+15x is divided by x^2-4x+3, the remainder is 5x +3. Find the values of a and b.

Answers

Answered by mohitkumar4245
0

Answer:

2x^4 + 3x^3 + 4x - 2x^2) (x + 3) .

Divide (2x^4 + 3x^3 + 4x - 2x^2) by (x + 3) 2x^3 - 3x^2 + 7x - 17 x + 3)2x^4 + 3x^3 - 2x^2 + 4x 2x^4 + 6x^3 - 3x^3 - 2x^2 + 4x - 3x^3 - 9x^2 7x^2 + 4x .

Step-by-step explanation:

Divide 30x^4 + 11x^3 - 82x^2 + 48 - 12x by 3x^2 + 2x - 4 and check the result by using division algorithm.

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