Question

when x is 2 and y is 3 and z is
(-4) x²+4xyz + y² + z²​

Answer 1

Answer:

(-4) x² + 4xyz + y² + z² = 0

(-4) (2)² + 4(2)(3)z + (3)² + z² = 0

-16 +24z +9 + z² = 0

-7 + 24z + z² = 0

24z + z² = 7

z + z² = 7/24

z + z = under root 1/4.

2z = 1/2

z = 1/2÷2

z = 1/2 × 1/2

z = 1/4.

Hope u got it... ☺️