Question

When x molecules are removed from from 200 mg of N
2
​
O, 2.89×10
−3
moles of N
2
​
O are left. x will be:

















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Answer 1

Answer:

Explanation:

Here, initial moles of N2O=  

44

200×10  

−3

 

​  

=4.55×10  

−3

 

moles removed = initial - final =4.55×10  

−3

−2.89×10  

−3

 

=1.66×10  

−3

moles

∴ no of molecules removed =6.022×10  

23

×1.66×10  

−3

 

=9.996×10  

20

 ≈10×10  

20

 

≈10  

21

molecules

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Answer 2

Answer:

Here, initial moles of N2O=  

44

200×10  

−3

 

​  

=4.55×10  

−3

 

moles removed = initial - final =4.55×10  

−3

−2.89×10  

−3

 

=1.66×10  

−3

moles

∴ no of molecules removed =6.022×10  

23

×1.66×10  

−3

 

=9.996×10  

20

≈10×10  

20

 

≈10  

21

molecules

hope it helps to you and mark as brainlist

Explanation: