Question

when x square - 3 divided by X 4 - 3 x cube minus x square + 9 x
minus 6​

Answer 1

Answer:

$\frac{ {x}^{4} - 3 {x}^{3} - {x}^{2} + 9x - 6 }{ {x}^{2} - 3} =$

the answer is

${x}^{2} - 3x + 2$

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