Question

when x+y=7 and xy= 12 then find the value of x square and y square​

Answer 1

Answer:

Given that, (x+y)=7, xy=12 and (x+y)²=x²+y²+2xy

$(x + y) = 7 \\ {(x + y)}^{2} = {(7)}^{2}\\ {x}^{2} + {y}^{2} + 2xy = 49 \\ {x}^{2} + {y}^{2} + 2(12) = 49 \\ {x}^{2} + {y}^{2} + 24 = 49 \\ {x}^{2} + {y}^{2} = 49 - 24 \\ \boxed{ {x}^{2} + {y}^{2} = 25}$

• x²+y²=25 is the right answer.