Math, asked by artartist26, 7 months ago

When (x³ + 31) is divided by (x + 1), the remainder is​

Answers

Answered by Anonymous
8

Answer:

  • Remainder is 30.

Solution:

Remainder theorem:

When a polynomial f (x)  is divided by \sf{x-\alpha}, then the remainder can be given by f (\alpha).

Comparing x + 1 and x-\alpha, we get

=> \alpha= -1

By Remainder theorem

f (x) = \sf{x^{3}+31}

Remainder = f (-1)

f (-1) = \sf{(-1)^{3}+31}

=> f (-1) = -1 + 31

=> f (-1) = 30

Hence, the remainder is 30.

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Extra information:

  • By remainder theorem we can say that when \sf{x^{n}+y^{n}} is divided by (x + y) then the remainder is \sf{(-y)^{n}+y^{n}}
Answered by mathsRSP
0

When a polynomial f (x)  is divided by , then the remainder can be given by f ().

Comparing x + 1 and x-, we get

=> = -1

By Remainder theorem

f (x) =

Remainder = f (-1)

f (-1) =

=> f (-1) = -1 + 31

=> f (-1) = 30

Hence, the remainder is 30.

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