When x3 + 4x2 – 3x + b is divided by x – 2, then
the remainder is the zero of another polynomial
23 – 19x2 + x – 19. Then the value of b is equal to
(a) -2
(b) -1
(C) 3 (d) 1
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X-2=0
X=2
Now,
X³+4x²-3x+b=0
(2)³+4(2)²-3(2)+b=0
8+16-6+b=0
8+10+b=0
18+b=0
b=-18
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