When x3-ax2+11x-6 is divided by x-4 the remainder is 6 . Find the value of a
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GIVEN :
When is divided by x-4 the remainder is 6 . Find the value of a
TO FIND :
The value of a
SOLUTION :
Given that when is divided by x-4 the remainder is 6 .
By using the Remainder theorem we can have that
f(4) = 6 and remainder=6
Put x=4 in
64-16a+44-6 = 6
-16a= 6-64-44+6
-16a=-96
16a=96
a = 6
∴ the value of a in the given expression is 6
Answered by
1
Answer:
= a = 6
solution is in the attached photo.
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