Math, asked by omkarpasi5067, 8 months ago

When x3-ax2+11x-6 is divided by x-4 the remainder is 6 . Find the value of a

Answers

Answered by ashishks1912
3

GIVEN :

When x^3-ax^2+11x-6 is divided by x-4 the remainder is 6 . Find the value of a

TO FIND :

The value of a

SOLUTION :

Given that when x^3-ax^2+11x-6 is divided by x-4 the remainder is 6 .

By using the Remainder theorem we can have that

f(4) = 6 and remainder=6

Put x=4 in x^3-ax^2+11x-6

4^3-a(4)^2+11(4)-6=6

64-16a+44-6 = 6

-16a= 6-64-44+6

-16a=-96

16a=96

a=\frac{96}{16}

a = 6

∴ the value of a in the given expression is 6

Answered by sshakuntala1977
1

Answer:

= a = 6

solution is in the attached photo.

Attachments:
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