When x³-ax²+6x-a is divided by x-1 the remainder is 2 points 7-a 7+a 7-2a 7+2a
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Hi friend
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Your answer
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Let f(x) = x³ - ax² + 6x - a
So,
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When,
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f(a) = x³ - ax² + 6x - a
=> (a)³ - a×(a)² + 6×a - a
=> a³ - a³ + 6a - a
=> 5a
Therefore,
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Remainder = 5a
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