when y=1 then x+3y+z =0 and -x-2z=0 find x and z
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Answer:
x= -6 , y=1 ,z=3
Step-by-step explanation:
It is given that, y=1.
Therefore,
x+3y+z=0
⇒x+3(1)+z=0
⇒x+y= -3 .........(i)
Now,
-x-2z =0 ...........(ii)
Therefore, by adding (i) & (ii)
we get z = 3
Substitute the value of z in (ii)
-x-2(3) = 0
⇒ -x-6 =0
⇒ x= -6.
Hope this helps!!
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