When you add two numbers and the number obtained by reversing the order of its digits is 165. Both both numbers differ by 3, find the number
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Answered by
4
Answer:
Let the digits of the number be x and y
(10x+y)+(10y+x)=165 &. x-y=3
11x+11y=165
x+y=15
x-y=3
2x=18
x=9
y=15–9=6
Therefore the number is 96 //
96+69=165 & 9–6=3.
Answered by
1
Answer:
Step-by-step explanation:
Let the digits of the number be x and y
(10x+y)+(10y+x)=165 &. x-y=3
11x+11y=165
x+y=15
x-y=3
2x=18
x=9
y=15–9=6
Therefore the number is 96
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