Math, asked by jarodmcguire, 19 hours ago

When you convert from larger units to smaller units, will your answer be a bigger or smaller number than what you started with? Why? Give an example.

Answers

Answered by sudhirkumar49557
2

Answer:

To convert from a larger unit to a smaller one, multiply. To convert from a smaller unit to a larger one, divide.

Answered by mukeshpateda2
0

Answer:

A-(2.0), B (0.1), C (4.5), D(0,c)

We take S(xy) as the centre of the circle →→ SA-SB SC

TS 15,17

Now, SA=SB Rightarrow SA^ 2 =SB^ 2 Rightarrow (x_{1} - 2) ^ 2 + (y_{1} + 0) ^ 2 =(x 1 - 0²+(x-1)² Rightarrow (y_{1} ^ 2 - 4x_{1} + 4) + (y_{1} ^ 2) =(x 1 ^ 2 )+(x 1 ^ 2 )+(x^ prime -2x,...,n

SUPER CIRCLE O

=>4x - 2v +1-4=0-4x-2y-3-0....(1) Also, SB-SC-SB²=SC²=(x)-0)²+(y)-1)=(x-4)²+(y-5)² Rightarrow (y_{t} ^ (Z')) + (y_{1} ^ (Z') - 2y_{1} + 1) = (y_{1} ^ (Z') - 8x_{1} + 16) + (y_{1} ^ (Z') - 10y_{1} + 25)

1 Mark

=8x-2y+10y;+1-16-25-0-8x+8y, -40-08(x; +y)-5)=0=x+y)-5=0...(2) Solving (1) & (2) we get the centre S(x1,y1)

1 Mark

2x(2) Rightarrow 2x_{1} + 2y_{1} - 10 =0..................(3)

(1)+(3)-6x-13-0-6x-13-x-13/6

(2) Rightarrow y_{1} = 5 - x_{1} = 5 - 13/6 = (30 - 13)/6 = 17 6 Rightarrow y 1 = 17 6

Centre of the

circle is S(x1,y1)=

1 Mark

Also, we have A=(2,0)

Hence, radius r=SA Rightarrow r ^ 2 = S * A ^ 2

therefore r ^ 2 = S * A ^ 2 = (2 - 13/6) ^ 2 + (0 - 17/6) ^ 2 = ((12 - 13)/6) ^ 2 + (17/6) ^ 2 = (1/36) + (289/36) = 290/36 .. Circle with Centre e(13/6, 17/6) and r ^ 2 = 290/36 * is * (x - 13/6) ^ 2 + (y - 17/6) ^ 2 = 290/36

Put D(0.c) in the above equation Rightarrow(0- 13 6 )^ 2 +(c- 17 6 )^ 2 = 290 36 Rightarrow (c - 17/6) ^ 2 = 290/36 - 169/36 = 121/(36/44)

Rightarrow ((6c - 17)/6) ^ 2 = 121 36 Rightarrow (6c-17)^ 2 36 = 11^ 2 36 Rightarrow6c-17= pm11

Rightarrow6c= pm11+17 Rightarrow6c=28 Rightarrow c = 28/beta = 14/3 * (or) * beta*c = beta Rightarrow c=1

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