When you flip a biased coin the probability of getting a tail is 0.2. How many times would you expect to get tails if you flip the coin 240 times?
Answers
Step-by-step explanation:
Consider the use of a binomial distribution expression as follows.
(a +b)^N = N!{Σ [a^(N-j+1)][b^(j-1)]/[(j-1)!][(N-j+1)!]}, with a =1/3, the chance not getting H and b = 2/3, the chance of getting H. 1 ≤ j ≤ (N+1) where N, in this case = number of coin flips = 3 and j-1 = the number of possible H’s regarding a particular outcome. Since a+b = 1, the sum of all possible outcomes, in this case, = 8, which are: TTT, HTT, THT, TTH, HHT, HTH, THH, HHH.
The probability of getting exactly 0H = 3![(1/3)^3][(2/3)^0]/(3!)(0!) = 1/27 = .037037…~ 3.7%.
The probability of getting exactly 1H = 3![(1/3)^2][(2/3)^1]/(2!)(1!) = 2/9 = .2222222…~ 22.2%.
The probability of getting exactly 2H = 3![(1/3)^1][(2/3)^2]/(1!)(2!) = 4/9 = =.444444…~ 44.4%.
The probability of getting exactly 3H = 3![(1/3)^0][(2/3)^3]/(0!)(3!) = 8/27 = .296296…~ 29.6%.
Answer:
48
Step-by-step explanation:
i got the question wrong on hegarty maths and 48 was the real answer. It is i swear on my life
(p.s i would show a screenshot but its not letting me. )